\(\int \frac {(a+c x^2)^3}{(d+e x)^{5/2}} \, dx\) [610]

Optimal result

Integrand size = 19, antiderivative size = 200 \[ \int \frac {\left (a+c x^2\right )^3}{(d+e x)^{5/2}} \, dx=-\frac {2 \left (c d^2+a e^2\right )^3}{3 e^7 (d+e x)^{3/2}}+\frac {12 c d \left (c d^2+a e^2\right )^2}{e^7 \sqrt {d+e x}}+\frac {6 c \left (c d^2+a e^2\right ) \left (5 c d^2+a e^2\right ) \sqrt {d+e x}}{e^7}-\frac {8 c^2 d \left (5 c d^2+3 a e^2\right ) (d+e x)^{3/2}}{3 e^7}+\frac {6 c^2 \left (5 c d^2+a e^2\right ) (d+e x)^{5/2}}{5 e^7}-\frac {12 c^3 d (d+e x)^{7/2}}{7 e^7}+\frac {2 c^3 (d+e x)^{9/2}}{9 e^7} \]

[Out]

-2/3*(a*e^2+c*d^2)^3/e^7/(e*x+d)^(3/2)-8/3*c^2*d*(3*a*e^2+5*c*d^2)*(e*x+d)^(3/2)/e^7+6/5*c^2*(a*e^2+5*c*d^2)*(
e*x+d)^(5/2)/e^7-12/7*c^3*d*(e*x+d)^(7/2)/e^7+2/9*c^3*(e*x+d)^(9/2)/e^7+12*c*d*(a*e^2+c*d^2)^2/e^7/(e*x+d)^(1/
2)+6*c*(a*e^2+c*d^2)*(a*e^2+5*c*d^2)*(e*x+d)^(1/2)/e^7

Rubi [A] (verified)

Time = 0.06 (sec) , antiderivative size = 200, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.053, Rules used = {711} \[ \int \frac {\left (a+c x^2\right )^3}{(d+e x)^{5/2}} \, dx=\frac {6 c^2 (d+e x)^{5/2} \left (a e^2+5 c d^2\right )}{5 e^7}-\frac {8 c^2 d (d+e x)^{3/2} \left (3 a e^2+5 c d^2\right )}{3 e^7}+\frac {6 c \sqrt {d+e x} \left (a e^2+c d^2\right ) \left (a e^2+5 c d^2\right )}{e^7}+\frac {12 c d \left (a e^2+c d^2\right )^2}{e^7 \sqrt {d+e x}}-\frac {2 \left (a e^2+c d^2\right )^3}{3 e^7 (d+e x)^{3/2}}+\frac {2 c^3 (d+e x)^{9/2}}{9 e^7}-\frac {12 c^3 d (d+e x)^{7/2}}{7 e^7} \]

[In]

Int[(a + c*x^2)^3/(d + e*x)^(5/2),x]

[Out]

(-2*(c*d^2 + a*e^2)^3)/(3*e^7*(d + e*x)^(3/2)) + (12*c*d*(c*d^2 + a*e^2)^2)/(e^7*Sqrt[d + e*x]) + (6*c*(c*d^2
+ a*e^2)*(5*c*d^2 + a*e^2)*Sqrt[d + e*x])/e^7 - (8*c^2*d*(5*c*d^2 + 3*a*e^2)*(d + e*x)^(3/2))/(3*e^7) + (6*c^2
*(5*c*d^2 + a*e^2)*(d + e*x)^(5/2))/(5*e^7) - (12*c^3*d*(d + e*x)^(7/2))/(7*e^7) + (2*c^3*(d + e*x)^(9/2))/(9*
e^7)

Rule 711

Int[((d_) + (e_.)*(x_))^(m_)*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[ExpandIntegrand[(d + e*x)^m*(a + c*
x^2)^p, x], x] /; FreeQ[{a, c, d, e, m}, x] && NeQ[c*d^2 + a*e^2, 0] && IGtQ[p, 0]

Rubi steps \begin{align*} \text {integral}& = \int \left (\frac {\left (c d^2+a e^2\right )^3}{e^6 (d+e x)^{5/2}}-\frac {6 c d \left (c d^2+a e^2\right )^2}{e^6 (d+e x)^{3/2}}+\frac {3 c \left (c d^2+a e^2\right ) \left (5 c d^2+a e^2\right )}{e^6 \sqrt {d+e x}}-\frac {4 c^2 d \left (5 c d^2+3 a e^2\right ) \sqrt {d+e x}}{e^6}+\frac {3 c^2 \left (5 c d^2+a e^2\right ) (d+e x)^{3/2}}{e^6}-\frac {6 c^3 d (d+e x)^{5/2}}{e^6}+\frac {c^3 (d+e x)^{7/2}}{e^6}\right ) \, dx \\ & = -\frac {2 \left (c d^2+a e^2\right )^3}{3 e^7 (d+e x)^{3/2}}+\frac {12 c d \left (c d^2+a e^2\right )^2}{e^7 \sqrt {d+e x}}+\frac {6 c \left (c d^2+a e^2\right ) \left (5 c d^2+a e^2\right ) \sqrt {d+e x}}{e^7}-\frac {8 c^2 d \left (5 c d^2+3 a e^2\right ) (d+e x)^{3/2}}{3 e^7}+\frac {6 c^2 \left (5 c d^2+a e^2\right ) (d+e x)^{5/2}}{5 e^7}-\frac {12 c^3 d (d+e x)^{7/2}}{7 e^7}+\frac {2 c^3 (d+e x)^{9/2}}{9 e^7} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.14 (sec) , antiderivative size = 171, normalized size of antiderivative = 0.86 \[ \int \frac {\left (a+c x^2\right )^3}{(d+e x)^{5/2}} \, dx=\frac {2 \left (-105 a^3 e^6+315 a^2 c e^4 \left (8 d^2+12 d e x+3 e^2 x^2\right )+63 a c^2 e^2 \left (128 d^4+192 d^3 e x+48 d^2 e^2 x^2-8 d e^3 x^3+3 e^4 x^4\right )+5 c^3 \left (1024 d^6+1536 d^5 e x+384 d^4 e^2 x^2-64 d^3 e^3 x^3+24 d^2 e^4 x^4-12 d e^5 x^5+7 e^6 x^6\right )\right )}{315 e^7 (d+e x)^{3/2}} \]

[In]

Integrate[(a + c*x^2)^3/(d + e*x)^(5/2),x]

[Out]

(2*(-105*a^3*e^6 + 315*a^2*c*e^4*(8*d^2 + 12*d*e*x + 3*e^2*x^2) + 63*a*c^2*e^2*(128*d^4 + 192*d^3*e*x + 48*d^2
*e^2*x^2 - 8*d*e^3*x^3 + 3*e^4*x^4) + 5*c^3*(1024*d^6 + 1536*d^5*e*x + 384*d^4*e^2*x^2 - 64*d^3*e^3*x^3 + 24*d
^2*e^4*x^4 - 12*d*e^5*x^5 + 7*e^6*x^6)))/(315*e^7*(d + e*x)^(3/2))

Maple [A] (verified)

Time = 2.40 (sec) , antiderivative size = 163, normalized size of antiderivative = 0.82

method	result	size
risch	\(\frac {2 c \left (35 c^{2} x^{4} e^{4}-130 x^{3} c^{2} d \,e^{3}+189 x^{2} a c \,e^{4}+345 x^{2} c^{2} d^{2} e^{2}-882 x a c d \,e^{3}-880 x \,c^{2} d^{3} e +945 a^{2} e^{4}+4599 a c \,d^{2} e^{2}+3335 c^{2} d^{4}\right ) \sqrt {e x +d}}{315 e^{7}}-\frac {2 \left (-18 x c d e +e^{2} a -17 c \,d^{2}\right ) \left (a^{2} e^{4}+2 a c \,d^{2} e^{2}+c^{2} d^{4}\right )}{3 e^{7} \left (e x +d \right )^{\frac {3}{2}}}\)	\(163\)
pseudoelliptic	\(\frac {\left (70 e^{6} x^{6}-120 d \,e^{5} x^{5}+240 d^{2} e^{4} x^{4}-640 x^{3} d^{3} e^{3}+3840 d^{4} e^{2} x^{2}+15360 d^{5} e x +10240 d^{6}\right ) c^{3}+16128 \left (\frac {3}{128} e^{4} x^{4}-\frac {1}{16} d \,e^{3} x^{3}+\frac {3}{8} d^{2} e^{2} x^{2}+\frac {3}{2} d^{3} e x +d^{4}\right ) e^{2} a \,c^{2}+5040 \left (\frac {3}{8} x^{2} e^{2}+\frac {3}{2} d e x +d^{2}\right ) e^{4} a^{2} c -210 e^{6} a^{3}}{315 \left (e x +d \right )^{\frac {3}{2}} e^{7}}\)	\(163\)
gosper	\(-\frac {2 \left (-35 x^{6} c^{3} e^{6}+60 x^{5} c^{3} d \,e^{5}-189 x^{4} a \,c^{2} e^{6}-120 x^{4} c^{3} d^{2} e^{4}+504 x^{3} a \,c^{2} d \,e^{5}+320 x^{3} c^{3} d^{3} e^{3}-945 x^{2} a^{2} c \,e^{6}-3024 x^{2} a \,c^{2} d^{2} e^{4}-1920 x^{2} c^{3} d^{4} e^{2}-3780 x \,a^{2} c d \,e^{5}-12096 x a \,c^{2} d^{3} e^{3}-7680 x \,c^{3} d^{5} e +105 e^{6} a^{3}-2520 d^{2} e^{4} a^{2} c -8064 d^{4} e^{2} c^{2} a -5120 c^{3} d^{6}\right )}{315 \left (e x +d \right )^{\frac {3}{2}} e^{7}}\)	\(205\)
trager	\(-\frac {2 \left (-35 x^{6} c^{3} e^{6}+60 x^{5} c^{3} d \,e^{5}-189 x^{4} a \,c^{2} e^{6}-120 x^{4} c^{3} d^{2} e^{4}+504 x^{3} a \,c^{2} d \,e^{5}+320 x^{3} c^{3} d^{3} e^{3}-945 x^{2} a^{2} c \,e^{6}-3024 x^{2} a \,c^{2} d^{2} e^{4}-1920 x^{2} c^{3} d^{4} e^{2}-3780 x \,a^{2} c d \,e^{5}-12096 x a \,c^{2} d^{3} e^{3}-7680 x \,c^{3} d^{5} e +105 e^{6} a^{3}-2520 d^{2} e^{4} a^{2} c -8064 d^{4} e^{2} c^{2} a -5120 c^{3} d^{6}\right )}{315 \left (e x +d \right )^{\frac {3}{2}} e^{7}}\)	\(205\)
derivativedivides	\(\frac {\frac {2 c^{3} \left (e x +d \right )^{\frac {9}{2}}}{9}-\frac {12 c^{3} d \left (e x +d \right )^{\frac {7}{2}}}{7}+\frac {6 a \,c^{2} e^{2} \left (e x +d \right )^{\frac {5}{2}}}{5}+6 c^{3} d^{2} \left (e x +d \right )^{\frac {5}{2}}-8 a \,c^{2} d \,e^{2} \left (e x +d \right )^{\frac {3}{2}}-\frac {40 c^{3} d^{3} \left (e x +d \right )^{\frac {3}{2}}}{3}+6 a^{2} c \,e^{4} \sqrt {e x +d}+36 a \,c^{2} d^{2} e^{2} \sqrt {e x +d}+30 c^{3} d^{4} \sqrt {e x +d}+\frac {12 c d \left (a^{2} e^{4}+2 a c \,d^{2} e^{2}+c^{2} d^{4}\right )}{\sqrt {e x +d}}-\frac {2 \left (e^{6} a^{3}+3 d^{2} e^{4} a^{2} c +3 d^{4} e^{2} c^{2} a +c^{3} d^{6}\right )}{3 \left (e x +d \right )^{\frac {3}{2}}}}{e^{7}}\)	\(229\)
default	\(\frac {\frac {2 c^{3} \left (e x +d \right )^{\frac {9}{2}}}{9}-\frac {12 c^{3} d \left (e x +d \right )^{\frac {7}{2}}}{7}+\frac {6 a \,c^{2} e^{2} \left (e x +d \right )^{\frac {5}{2}}}{5}+6 c^{3} d^{2} \left (e x +d \right )^{\frac {5}{2}}-8 a \,c^{2} d \,e^{2} \left (e x +d \right )^{\frac {3}{2}}-\frac {40 c^{3} d^{3} \left (e x +d \right )^{\frac {3}{2}}}{3}+6 a^{2} c \,e^{4} \sqrt {e x +d}+36 a \,c^{2} d^{2} e^{2} \sqrt {e x +d}+30 c^{3} d^{4} \sqrt {e x +d}+\frac {12 c d \left (a^{2} e^{4}+2 a c \,d^{2} e^{2}+c^{2} d^{4}\right )}{\sqrt {e x +d}}-\frac {2 \left (e^{6} a^{3}+3 d^{2} e^{4} a^{2} c +3 d^{4} e^{2} c^{2} a +c^{3} d^{6}\right )}{3 \left (e x +d \right )^{\frac {3}{2}}}}{e^{7}}\)	\(229\)

[In]

int((c*x^2+a)^3/(e*x+d)^(5/2),x,method=_RETURNVERBOSE)

[Out]

2/315*c*(35*c^2*e^4*x^4-130*c^2*d*e^3*x^3+189*a*c*e^4*x^2+345*c^2*d^2*e^2*x^2-882*a*c*d*e^3*x-880*c^2*d^3*e*x+
945*a^2*e^4+4599*a*c*d^2*e^2+3335*c^2*d^4)*(e*x+d)^(1/2)/e^7-2/3*(-18*c*d*e*x+a*e^2-17*c*d^2)*(a^2*e^4+2*a*c*d
^2*e^2+c^2*d^4)/e^7/(e*x+d)^(3/2)

Fricas [A] (verification not implemented)

none

Time = 0.45 (sec) , antiderivative size = 223, normalized size of antiderivative = 1.12 \[ \int \frac {\left (a+c x^2\right )^3}{(d+e x)^{5/2}} \, dx=\frac {2 \, {\left (35 \, c^{3} e^{6} x^{6} - 60 \, c^{3} d e^{5} x^{5} + 5120 \, c^{3} d^{6} + 8064 \, a c^{2} d^{4} e^{2} + 2520 \, a^{2} c d^{2} e^{4} - 105 \, a^{3} e^{6} + 3 \, {\left (40 \, c^{3} d^{2} e^{4} + 63 \, a c^{2} e^{6}\right )} x^{4} - 8 \, {\left (40 \, c^{3} d^{3} e^{3} + 63 \, a c^{2} d e^{5}\right )} x^{3} + 3 \, {\left (640 \, c^{3} d^{4} e^{2} + 1008 \, a c^{2} d^{2} e^{4} + 315 \, a^{2} c e^{6}\right )} x^{2} + 12 \, {\left (640 \, c^{3} d^{5} e + 1008 \, a c^{2} d^{3} e^{3} + 315 \, a^{2} c d e^{5}\right )} x\right )} \sqrt {e x + d}}{315 \, {\left (e^{9} x^{2} + 2 \, d e^{8} x + d^{2} e^{7}\right )}} \]

[In]

integrate((c*x^2+a)^3/(e*x+d)^(5/2),x, algorithm="fricas")

[Out]

2/315*(35*c^3*e^6*x^6 - 60*c^3*d*e^5*x^5 + 5120*c^3*d^6 + 8064*a*c^2*d^4*e^2 + 2520*a^2*c*d^2*e^4 - 105*a^3*e^
6 + 3*(40*c^3*d^2*e^4 + 63*a*c^2*e^6)*x^4 - 8*(40*c^3*d^3*e^3 + 63*a*c^2*d*e^5)*x^3 + 3*(640*c^3*d^4*e^2 + 100
8*a*c^2*d^2*e^4 + 315*a^2*c*e^6)*x^2 + 12*(640*c^3*d^5*e + 1008*a*c^2*d^3*e^3 + 315*a^2*c*d*e^5)*x)*sqrt(e*x +
d)/(e^9*x^2 + 2*d*e^8*x + d^2*e^7)

Sympy [A] (verification not implemented)

Time = 3.29 (sec) , antiderivative size = 252, normalized size of antiderivative = 1.26 \[ \int \frac {\left (a+c x^2\right )^3}{(d+e x)^{5/2}} \, dx=\begin {cases} \frac {2 \left (- \frac {6 c^{3} d \left (d + e x\right )^{\frac {7}{2}}}{7 e^{6}} + \frac {c^{3} \left (d + e x\right )^{\frac {9}{2}}}{9 e^{6}} + \frac {6 c d \left (a e^{2} + c d^{2}\right )^{2}}{e^{6} \sqrt {d + e x}} + \frac {\left (d + e x\right )^{\frac {5}{2}} \cdot \left (3 a c^{2} e^{2} + 15 c^{3} d^{2}\right )}{5 e^{6}} + \frac {\left (d + e x\right )^{\frac {3}{2}} \left (- 12 a c^{2} d e^{2} - 20 c^{3} d^{3}\right )}{3 e^{6}} + \frac {\sqrt {d + e x} \left (3 a^{2} c e^{4} + 18 a c^{2} d^{2} e^{2} + 15 c^{3} d^{4}\right )}{e^{6}} - \frac {\left (a e^{2} + c d^{2}\right )^{3}}{3 e^{6} \left (d + e x\right )^{\frac {3}{2}}}\right )}{e} & \text {for}\: e \neq 0 \\\frac {a^{3} x + a^{2} c x^{3} + \frac {3 a c^{2} x^{5}}{5} + \frac {c^{3} x^{7}}{7}}{d^{\frac {5}{2}}} & \text {otherwise} \end {cases} \]

[In]

integrate((c*x**2+a)**3/(e*x+d)**(5/2),x)

[Out]

Piecewise((2*(-6*c**3*d*(d + e*x)**(7/2)/(7*e**6) + c**3*(d + e*x)**(9/2)/(9*e**6) + 6*c*d*(a*e**2 + c*d**2)**
2/(e**6*sqrt(d + e*x)) + (d + e*x)**(5/2)*(3*a*c**2*e**2 + 15*c**3*d**2)/(5*e**6) + (d + e*x)**(3/2)*(-12*a*c*
*2*d*e**2 - 20*c**3*d**3)/(3*e**6) + sqrt(d + e*x)*(3*a**2*c*e**4 + 18*a*c**2*d**2*e**2 + 15*c**3*d**4)/e**6 -
(a*e**2 + c*d**2)**3/(3*e**6*(d + e*x)**(3/2)))/e, Ne(e, 0)), ((a**3*x + a**2*c*x**3 + 3*a*c**2*x**5/5 + c**3
*x**7/7)/d**(5/2), True))

Maxima [A] (verification not implemented)

none

Time = 0.22 (sec) , antiderivative size = 215, normalized size of antiderivative = 1.08 \[ \int \frac {\left (a+c x^2\right )^3}{(d+e x)^{5/2}} \, dx=\frac {2 \, {\left (\frac {35 \, {\left (e x + d\right )}^{\frac {9}{2}} c^{3} - 270 \, {\left (e x + d\right )}^{\frac {7}{2}} c^{3} d + 189 \, {\left (5 \, c^{3} d^{2} + a c^{2} e^{2}\right )} {\left (e x + d\right )}^{\frac {5}{2}} - 420 \, {\left (5 \, c^{3} d^{3} + 3 \, a c^{2} d e^{2}\right )} {\left (e x + d\right )}^{\frac {3}{2}} + 945 \, {\left (5 \, c^{3} d^{4} + 6 \, a c^{2} d^{2} e^{2} + a^{2} c e^{4}\right )} \sqrt {e x + d}}{e^{6}} - \frac {105 \, {\left (c^{3} d^{6} + 3 \, a c^{2} d^{4} e^{2} + 3 \, a^{2} c d^{2} e^{4} + a^{3} e^{6} - 18 \, {\left (c^{3} d^{5} + 2 \, a c^{2} d^{3} e^{2} + a^{2} c d e^{4}\right )} {\left (e x + d\right )}\right )}}{{\left (e x + d\right )}^{\frac {3}{2}} e^{6}}\right )}}{315 \, e} \]

[In]

integrate((c*x^2+a)^3/(e*x+d)^(5/2),x, algorithm="maxima")

[Out]

2/315*((35*(e*x + d)^(9/2)*c^3 - 270*(e*x + d)^(7/2)*c^3*d + 189*(5*c^3*d^2 + a*c^2*e^2)*(e*x + d)^(5/2) - 420
*(5*c^3*d^3 + 3*a*c^2*d*e^2)*(e*x + d)^(3/2) + 945*(5*c^3*d^4 + 6*a*c^2*d^2*e^2 + a^2*c*e^4)*sqrt(e*x + d))/e^
6 - 105*(c^3*d^6 + 3*a*c^2*d^4*e^2 + 3*a^2*c*d^2*e^4 + a^3*e^6 - 18*(c^3*d^5 + 2*a*c^2*d^3*e^2 + a^2*c*d*e^4)*
(e*x + d))/((e*x + d)^(3/2)*e^6))/e

Giac [A] (verification not implemented)

none

Time = 0.28 (sec) , antiderivative size = 258, normalized size of antiderivative = 1.29 \[ \int \frac {\left (a+c x^2\right )^3}{(d+e x)^{5/2}} \, dx=\frac {2 \, {\left (18 \, {\left (e x + d\right )} c^{3} d^{5} - c^{3} d^{6} + 36 \, {\left (e x + d\right )} a c^{2} d^{3} e^{2} - 3 \, a c^{2} d^{4} e^{2} + 18 \, {\left (e x + d\right )} a^{2} c d e^{4} - 3 \, a^{2} c d^{2} e^{4} - a^{3} e^{6}\right )}}{3 \, {\left (e x + d\right )}^{\frac {3}{2}} e^{7}} + \frac {2 \, {\left (35 \, {\left (e x + d\right )}^{\frac {9}{2}} c^{3} e^{56} - 270 \, {\left (e x + d\right )}^{\frac {7}{2}} c^{3} d e^{56} + 945 \, {\left (e x + d\right )}^{\frac {5}{2}} c^{3} d^{2} e^{56} - 2100 \, {\left (e x + d\right )}^{\frac {3}{2}} c^{3} d^{3} e^{56} + 4725 \, \sqrt {e x + d} c^{3} d^{4} e^{56} + 189 \, {\left (e x + d\right )}^{\frac {5}{2}} a c^{2} e^{58} - 1260 \, {\left (e x + d\right )}^{\frac {3}{2}} a c^{2} d e^{58} + 5670 \, \sqrt {e x + d} a c^{2} d^{2} e^{58} + 945 \, \sqrt {e x + d} a^{2} c e^{60}\right )}}{315 \, e^{63}} \]

[In]

integrate((c*x^2+a)^3/(e*x+d)^(5/2),x, algorithm="giac")

[Out]

2/3*(18*(e*x + d)*c^3*d^5 - c^3*d^6 + 36*(e*x + d)*a*c^2*d^3*e^2 - 3*a*c^2*d^4*e^2 + 18*(e*x + d)*a^2*c*d*e^4
- 3*a^2*c*d^2*e^4 - a^3*e^6)/((e*x + d)^(3/2)*e^7) + 2/315*(35*(e*x + d)^(9/2)*c^3*e^56 - 270*(e*x + d)^(7/2)*
c^3*d*e^56 + 945*(e*x + d)^(5/2)*c^3*d^2*e^56 - 2100*(e*x + d)^(3/2)*c^3*d^3*e^56 + 4725*sqrt(e*x + d)*c^3*d^4
*e^56 + 189*(e*x + d)^(5/2)*a*c^2*e^58 - 1260*(e*x + d)^(3/2)*a*c^2*d*e^58 + 5670*sqrt(e*x + d)*a*c^2*d^2*e^58
+ 945*sqrt(e*x + d)*a^2*c*e^60)/e^63

Mupad [B] (verification not implemented)

Time = 9.47 (sec) , antiderivative size = 225, normalized size of antiderivative = 1.12 \[ \int \frac {\left (a+c x^2\right )^3}{(d+e x)^{5/2}} \, dx=\frac {\left (30\,c^3\,d^2+6\,a\,c^2\,e^2\right )\,{\left (d+e\,x\right )}^{5/2}}{5\,e^7}+\frac {\sqrt {d+e\,x}\,\left (6\,a^2\,c\,e^4+36\,a\,c^2\,d^2\,e^2+30\,c^3\,d^4\right )}{e^7}-\frac {\frac {2\,a^3\,e^6}{3}-\left (d+e\,x\right )\,\left (12\,a^2\,c\,d\,e^4+24\,a\,c^2\,d^3\,e^2+12\,c^3\,d^5\right )+\frac {2\,c^3\,d^6}{3}+2\,a\,c^2\,d^4\,e^2+2\,a^2\,c\,d^2\,e^4}{e^7\,{\left (d+e\,x\right )}^{3/2}}+\frac {2\,c^3\,{\left (d+e\,x\right )}^{9/2}}{9\,e^7}-\frac {\left (40\,c^3\,d^3+24\,a\,c^2\,d\,e^2\right )\,{\left (d+e\,x\right )}^{3/2}}{3\,e^7}-\frac {12\,c^3\,d\,{\left (d+e\,x\right )}^{7/2}}{7\,e^7} \]

[In]

int((a + c*x^2)^3/(d + e*x)^(5/2),x)

[Out]

((30*c^3*d^2 + 6*a*c^2*e^2)*(d + e*x)^(5/2))/(5*e^7) + ((d + e*x)^(1/2)*(30*c^3*d^4 + 6*a^2*c*e^4 + 36*a*c^2*d
^2*e^2))/e^7 - ((2*a^3*e^6)/3 - (d + e*x)*(12*c^3*d^5 + 24*a*c^2*d^3*e^2 + 12*a^2*c*d*e^4) + (2*c^3*d^6)/3 + 2
*a*c^2*d^4*e^2 + 2*a^2*c*d^2*e^4)/(e^7*(d + e*x)^(3/2)) + (2*c^3*(d + e*x)^(9/2))/(9*e^7) - ((40*c^3*d^3 + 24*
a*c^2*d*e^2)*(d + e*x)^(3/2))/(3*e^7) - (12*c^3*d*(d + e*x)^(7/2))/(7*e^7)